0.002x^2=0.2x

Solution for 0.002x^2=0.2x equation:

0.002x^2=0.2x

We move all terms to the left:

0.002x^2-(0.2x)=0

We add all the numbers together, and all the variables

0.002x^2-(+0.2x)=0

We get rid of parentheses

0.002x^2-0.2x=0

a = 0.002; b = -0.2; c = 0;
Δ = b2-4ac
Δ = -0.22-4·0.002·0
Δ = 0.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.2)-\sqrt{0.04}}{2*0.002}=\frac{0.2-\sqrt{0.04}}{0.004}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.2)+\sqrt{0.04}}{2*0.002}=\frac{0.2+\sqrt{0.04}}{0.004}
$